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Ensuring the passengers\\u2019 safety and security requires the driver to have the knowledge, skill, and experience to control the vehicle when confronted with an emergency. The emergency does not necessarily need to be a security scenario; it can often be an accident-producing situation.\\xa0

As we have mentioned many times in the past, research and science define driving skill as the driver\\u2019s \\u201cability\\u201d to use the vehicle\\u2019s \\u201ccapability.\\u201d

Former\\xa0VDI\\xa0or Scotti School students know that we were and are anal about training our students to maximize the vehicle\\u2019s capability. The more of the vehicle\\u2019s capability the security driver can use, the higher the probability that the driver will avoid an accident or other life-threatening scenario.\\xa0

To pass the VDI course or be\\xa0certified as an ISDA Security Driver, a driver must demonstrate they can use a minimum of 80% of the vehicle\\u2019s capability.

The simple scientific fact is that every tenth of a percent that VDI can train the driver\\u2019s ability to use the vehicle\\u2019s capability is a lifesaving skill. But it is hard to conceptualize how a 1% increase in driver ability increases the principal and passengers\\u2019 safety and security; hence, an explanation is in order.

Safety/Security and the Concept of G\\u2019S

We need to explain the G forces\\u2019 effect on the Driver/ Principal/Vehicle safety and security.

The best way to understand a specific vehicle\\u2019s safety dynamics is by understanding how G-forces affect the driver/vehicle\\u2019s capability to stay in control. Anytime the steering wheel is moved while the car is in motion, a lateral or sideways force is created. This force is pushing in the opposite direction the car is turning.\\xa0

The term G\\u2019s is a measurement of the force acting on the car. It is this force that determines if the driver can stay in control of their vehicle. A tenth of a G can make the difference between avoiding a potential accident or vehicle attack scenario \\u2013 or not.

Scenario A \\u2013 at a given speed, if the path of a 4,000 Lb/1814.4 Kg car is altered in a way that produces one G, that one G of force is equivalent to 4,000 Lb/1814.4 Kg of force pushing on the vehicle center of gravity (CG) pushing the vehicle away from its desired path.

There is a simple equation that is used to determine the amount of force pushing on the vehicle. The amount of force pushing on the car is equal to the G\\u2019s times the vehicle\\u2019s weight.\\xa0\\xa0

Scenario B \\u2013 At that same given speed in scenario A, if we turned the steering wheel of our 4,000 Lb/1814.4 Kg car in such a way that .7G was created, then we would have created 2,800 lbs./1270 Kg of force. We came to those numbers by multiply the vehicle weight times .7 G\\u2019s or 4,000/1814.4 Kg X .7 g\\u2019s = 2,800 lbs./1270 Kg.\\xa0\\xa0

If the car weighed 3,000 lbs/1361 Kg and the steering wheel was turned the same number of degrees at the same speed, and the vehicle took the same path, the equation would read 3,000 lbs/1361 Kg (the vehicle weight) \\xa0X .7 g\\u2019s or 2,100 lbs/953 Kg of force, and so forth.\\xa0

Understand the lateral G-forces created in a turn are based upon both the vehicle\\u2019s speed, weight, and how much the steering wheel is moved or the degree, or sharpness, of the turn.

The purpose of using G\\u2019s as a measuring tool

G\\u2019s are used as a measurement of driving skills and method of testing vehicle capability. The purpose of using G\\u2019s instead of weight for a measuring tool is because saying that \\u201cthere are 2,800 lbs./1270 Kg. of force being exerted on the car\\u201d does not tell us very much.\\xa0\\xa0

The 2,800 lbs./1270 Kg. of force number is meaningless unless the weight of the car is also known.\\xa0For instance, if 3,000 lbs/1361 Kg of force is exerted on a 5,000 lb/2268Kg car, that\\u2019s no big problem.\\xa0

However, if you take a corner in such a way that 3,000 lbs/1361 Kg. is being exerted on a 2,000 lb/907 Kg car, you\\u2019re in big trouble.\\xa0

It\\u2019s far easier to say, \\u201cThis vehicle is designed to absorb .7 Gs.\\u201d If we use a 5,000 lb/2268Kg car for this example, then .7 Gs means the vehicle can absorb 3,500 lbs/1588 Kg of force before becoming unstable. (5,000 lb/2268Kg x .7 g\\u2019s)\\xa0

If we use our lightweight 2,000 lb/907 Kg car, then that .7 Gs is the equivalent of 1,400 lbs./635 Kg of force. (2,000 lb/907 Kg x .7 g\\u2019s)\\xa0

G\\u2019S X WEIGHT OF CAR = HOW MUCH WEIGHT (FORCE) IS PUSHING ON THE CAR.

Now to the original question

\\xa0Why for decades have we been adamant about ensuring students reach 80% or more of the vehicle\\u2019s capability, and while conducting training, the instructors will spend an inordinate amount of time ensuring you can use every tenth of a G the vehicle offers?

The answer \\u2013 a tenth of a G could mean the difference between surviving or not surviving. Here is an example:

Using the science of driving and applying metrics and equations that are familiar and often used in accident reconstruction technology, we can conceptualize the value of adding .1 G to the driver skill level.

If the vehicle is traveling 40 MPH/64.4 KPH in a vehicle/driver combination that can handle at .85 G\\u2019s, and there was an object (barrier) that measures 10 Feet/3.1 Meters wide in front of the driver, they would need approximately 49 Feet/15 Meters of distance to clear the barrier.

With all the parameters the same as above, such as vehicle position and speed (40 MPH/64.4 KPH) with a Vehicle/Driver combination that handled at .7 G\\u2019s, The driver would need approximately 55 Feet/17 Meters of distance to clear a barrier that 10 Feet/3.1 Meters.

If traveling 40 MPH/64.4 KPH with a Vehicle/Driver combination that handled at .6 G\\u2019s, the driver would need approximately 59 Feet / 18 Meters distance to clear a barrier that is 10 Feet/3.1 meters.

Same scenario traveling 40 MPH/64.4 KPH but now with a Vehicle/Driver combination that handled at .5 G\\u2019s the driver would need approximately 65 Feet/19.8 Meters distance to clear a 10 Feet/3.1 Meter barrier.

With all the parameters the same as above, such as vehicle position and speed (40 MPH/64.4 KPH) but now with a Driver/Vehicle combination that can handle only .4 G\\u2019s, they would need approximately 72 Feet/ 22 Meters of distance to clear the same barrier.

Every 10th of a G that you can use gives you more time and distance to drive out of the problem \\u2013 this is why computers are needed to measure the driver\\u2019s ability to use the vehicle\\u2019s capability.

These measurements can be computed using a radar gun and accurately measuring the vehicle\\u2019s path through individual exercises.\\xa0

Understanding the concept of lateral acceleration is a must for a security driver.

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